Algebra: Chapter 13, Lesson 2, page 580.
More Solving Quadratic Equations
Solve a quadratic equation of the form `ax^2 = k`
Example: `-3x^2 + 7 = 0` becomes …
`-3x^2 = -7` or `x^2=7/3`
then `x = ±sqrt(7/3)`, don’t forget to rationalize this to `x = ±sqrt(21)/3`!
Solve a quadratic equation by factoring one expression into a binomial square [of the form `(x + a)^2 = k`]
Example: `(x-5)^2 = 9`, if you take the square root of both sides becomes …
`x-5 = ±sqrt(9)` or `x = 5 ±sqrt(9)` or `x = 5 ± 3` or `x=8` or `x=2`
Two of tonight’s homework problems solved by MrE are here! Just click it.
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Algebra 1a: CST Review – Area of a Parallelogram, Triangle and Trapezoid
Definitions: `b` is the base and `h` is the height of the geometric figure below. Remember too, that the base and the height are at RIGHT ANGLES to each other!
Area, of a Triangle, `A = (b*h)/2` which is the same thing as `(1/2) * b * h`
Area of a Parallelogram, `A= b*h`.
Area of a Trapezoid, `A = (1/2) * h * (b_1 + b_2)` which is the same thing as `[h * (b_1 + b_2)]/2`