Day 117 – March 1

Algebra: Chapter 10, Lesson 8, page 460.

Mixture Problems

Whether they are acid mixes or coffee bean blends or mixed nuts, we treat these problems the same. `x` will stand for the amount of one of the mixes and the (total amount – x) is the amount of the other mix. Convert percentages to decimals (remember `D2P`?) and use monetary cost per pound as decimals (like 2 dollars and 4 cents is equal to 2.04) and you’ll be fine.

`CA + CA = CA` (oops!)

where:

`C` = concentration (in decimals, convert from percentages)

`A` = amount

The problems CAN be solved with 2 variables, `x` and `y`, BUT it requires 2 equations and substitution – I think it is just twice the work of developing one equation with just 1 variable. For these problems, the book and I agree on the easiest method!

Here is a great Purplemath link.

Two of tonight’s homework problems solved by MrE are here! Just click it

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Algebra 1a: Chapter 8, Lesson 4, page 373.

Using systems of equations

Steps to solve systems of equations can be:

  • Graph the equations
  • Substitution of one variable in terms of the other
  • Adding or subtracting the 2 equations

Before you start attacking the word problem, make sure you have a plan of attack such as:

  • Understand the problem
  • Develop and carry out a PLAN
  • Find the ANSWER and CHECK

Click here for a pretty good link from purplemath.com with examples.

Two of tonight’s homework problems solved by MrE are here! Just click it!

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