Day 131 – March 21

Algebra: Chapter 11, Lesson 7 and Lesson 8, page 509 and 514.

Theorem of Pythagoras and its Uses

`c^2 = a^2 + b^2`,

where `a`, `b` and `c` are the sides of a RIGHT TRIANGLE. `a` and `b` are considered the sides of the triangle where `c` (opposite of the right angle) is called the hypotenuse.

The distance formula is a derivation of the Pythagorean Theorem and you can use it to find the distance from one coordinate point to another. Just remember, like in the slope equation, DON’T MIX UP THE DIRECTION that you define as `x_1` and `y_1`, they both go the same way!

`d = sqrt((x_1 – x_2)^2 + (y_1 – y_2)^2)`

Here is another quick explanation of the Theorem of Pythagoras and the Distance Formula.

Use a calculator with a `sqrt` key, it will make the word problems much easier to do!

Two of tonight’s homework problems solved by MrE are here! Just click it.

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Algebra 1a: Chapter 9, Lesson 3, page 411.

Equations and Absolute Value

To solve an equation of the form `| A | = b`, solve the disjunction `A = b` OR `A = −b`. You will have 2 equations to solve with the right side of the second equation having the opposite sign of the first equation’s right side.

REMEMBER by definition, the solution of `| A | ≠ a` NEGATIVE NUMBER! So … the solution to these type of problems is the NULL SET! or the symbol `∅` !

Here is a link to examples!

Two of tonight’s homework problems solved by MrE are here! Just click it!

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